How many grams of oxygen gas are required to react completely with 14.6 g of solid sodium to form sodium oxide, Na2O(s)?
To determine the grams of oxygen gas, we need to calculate the stoichiometry of the balanced chemical equation for the reaction between sodium and oxygen gas.
The balanced equation for the reaction is:
4 Na(s) + O2(g) → 2 Na2O(s)
From the balanced equation, we see that 4 moles of sodium react with 1 mole of oxygen gas to produce 2 moles of sodium oxide.
To find the moles of sodium, we divide the mass of sodium by its molar mass:
Molar mass of Na = 22.99 g/mol
Moles of sodium = mass of sodium / molar mass of sodium = 14.6 g / 22.99 g/mol = 0.6351 mol
From the balanced equation, we know that the ratio of sodium to oxygen gas is 4:1. So, the moles of oxygen gas required can be found using the mole ratio:
Moles of oxygen gas = (Moles of sodium) / 4 = 0.6351 mol / 4 = 0.1588 mol
To find the mass of oxygen gas, we multiply the moles of oxygen gas by its molar mass:
Molar mass of O2 = 2 * 16.00 g/mol = 32.00 g/mol
Mass of oxygen gas = moles of oxygen gas * molar mass of O2 = 0.1588 mol * 32.00 g/mol = 5.08 g
Therefore, 5.08 grams of oxygen gas are required to completely react with 14.6 grams of solid sodium and form sodium oxide, Na2O(s).
To find the number of grams of oxygen gas required to react completely with 14.6 g of solid sodium, we need to use the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between sodium and oxygen gas to form sodium oxide is:
4 Na(s) + O2(g) → 2 Na2O(s)
From the balanced equation, we can see that 4 moles of sodium react with 1 mole of oxygen gas to produce 2 moles of sodium oxide.
Step 1: Calculate the moles of sodium
To calculate the moles of sodium, we'll use the molar mass of sodium (Na), which is 22.99 g/mol.
Moles of sodium = Mass of sodium / Molar mass of sodium
Moles of sodium = 14.6 g / 22.99 g/mol
Step 2: Determine the moles of oxygen gas needed
From the balanced equation, we can see that the mole ratio between sodium and oxygen gas is 4:1. Therefore, the moles of oxygen gas needed will be one-fourth of the moles of sodium.
Moles of oxygen gas = Moles of sodium / 4
Step 3: Calculate the mass of oxygen gas
To calculate the mass of oxygen gas, we'll use the molar mass of oxygen (O2), which is 32.00 g/mol.
Mass of oxygen gas = Moles of oxygen gas × Molar mass of oxygen
Mass of oxygen gas = (Moles of sodium / 4) × 32.00 g/mol
Substitute the value of "Moles of sodium" calculated earlier into the equation and solve for "Mass of oxygen gas."
Finally, substitute the values into the equation and calculate:
Moles of sodium = 14.6 g / 22.99 g/mol = 0.634 mol
Moles of oxygen gas = 0.634 mol / 4 = 0.1585 mol
Mass of oxygen gas = 0.1585 mol × 32.00 g/mol = 5.072 g
Therefore, approximately 5.072 grams of oxygen gas are required to react completely with 14.6 grams of solid sodium to form sodium oxide, Na2O(s).