in a right triangle if the adjacent A = 16, and the hypotenuse C = 20 then what is the oppisite B.
Juleana/Cassandra -- I showed you how to do the last problem.
Let's see you try this one.
I'll be glad to check your answer.
also for this one i got, 19.2. but that is a clueless guess, using info i remember, from previous classes.
a^2 + b^2 = c^2
16^2 + b^2 = 20^2
256 + b^2 = 400
b^2 = 400 - 256
b^2 = 144
b = 12
thank you so much, i'll try to figure out the real question now.
You're welcome. :-)
In a right triangle, the side opposite an angle is referred to as the "opposite" side. In this case, we are given the length of the adjacent side (A) and the length of the hypotenuse (C), and we need to find the length of the opposite side (B).
To solve this, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (C) is equal to the sum of the squares of the lengths of the other two sides (A and B). Mathematically, it can be represented as:
C^2 = A^2 + B^2
Let's substitute the values we have into the equation:
20^2 = 16^2 + B^2
Simplifying,
400 = 256 + B^2
Now, let's solve for B^2:
B^2 = 400 - 256
B^2 = 144
To find B, we need to take the square root of both sides:
B = √144
B = 12
Therefore, the length of the opposite side (B) is 12 in this right triangle.