Can you please solve
alogX=lnX
Logy=log e * ln y will allow you to convert.
X=I
To solve the equation alogX = lnX, we need to isolate the variable X.
First, let's rewrite lnX using the natural logarithm base e.
lnX = logeX
Now, we can use the properties of logarithms to solve the equation.
Using the property logy = loge * ln y, we can rewrite the equation as:
alogX = loge * lnX
Now, we can equate the two expressions inside the parentheses:
alogX = logeX
Since the bases of the logarithms are the same (both a and e), we can set the exponents equal to each other:
logX = 1
Now, we can solve for X by taking both sides as exponents with base 10:
10^(logX) = 10^1
X = 10
So, the solution to the equation alogX = lnX is X = 10.