2g NaHCO3 + .6 mL HCL --> NaCl+CO2+H2O
How much carbon dioxide do I get? How do I find out?
I got 410 mL of CO2, is this correct?
1. Is this a limiting reagent problem? If so, there is no volume HCl given in the problem.
2. Do you want volume of CO2 or grams CO2. "How much" doesn't say which.
To find out how much carbon dioxide (CO2) you will get from the reaction between 2g of NaHCO3 and 0.6 mL of HCl, you need to use stoichiometry and the balanced chemical equation.
First, write and balance the chemical equation:
2 NaHCO3 + 2 HCl → 2 NaCl + CO2 + H2O
From the balanced equation, you can see that 2 moles of NaHCO3 react with 2 moles of HCl to produce 1 mole of CO2.
To determine the amount of CO2 produced, you need to convert the mass of NaHCO3 to moles by using the molar mass. The molar mass of NaHCO3 is calculated as follows:
(1 x atomic mass of Na) + (1 x atomic mass of H) + (1 x atomic mass of C) + (3 x atomic mass of O) = 23 + 1 + 12 + (3 x 16) = 84 g/mol
Now, you can calculate the number of moles of NaHCO3:
moles of NaHCO3 = mass / molar mass = 2 g / 84 g/mol
Next, use the stoichiometric ratio to determine the moles of CO2 produced. From the equation, you can see that 2 moles of NaHCO3 produce 1 mole of CO2.
moles of CO2 = moles of NaHCO3 × (1 mole CO2 / 2 moles NaHCO3)
Finally, convert the moles of CO2 to volume using the ideal gas law, assuming standard temperature and pressure (STP), which is 0 degrees Celsius and 1 atmosphere (atm) respectively. At STP, 1 mole of any ideal gas occupies 22.4 liters.
volume of CO2 = moles of CO2 × 22.4 L/mol
Follow these steps to calculate the amount of carbon dioxide produced and compare it to your answer of 410 mL.