What is the molar concentration of calcium hydroxide that has 0.185g solute in 100ml solution?
Convert 0.185 g Ca(OH)2 to moles. moles = grma/molar mass.
Then M = mols/L soln.
To find the molar concentration, also known as molarity, of calcium hydroxide (Ca(OH)2), you need to follow a series of steps:
Step 1: Calculate the number of moles of calcium hydroxide (Ca(OH)2).
To do this, you need to know the molar mass of calcium hydroxide, which is calculated by adding the atomic masses of the elements:
Ca: 40.08 g/mol (molar mass of calcium)
O: 16.00 g/mol (molar mass of oxygen)
H: 1.01 g/mol (molar mass of hydrogen)
Total molar mass of calcium hydroxide: (40.08 g/mol × 1) + (16.00 g/mol × 2) + (1.01 g/mol × 2) = 74.10 g/mol
To find the number of moles, divide the mass of solute (0.185 g) by the molar mass:
Number of moles = mass / molar mass = 0.185 g / 74.10 g/mol
Step 2: Determine the volume of the solution in liters.
The volume of the solution is given as 100 ml. To convert it to liters, divide by 1000:
Volume of solution = 100 ml / 1000 ml/L = 0.1 L
Step 3: Calculate the molar concentration (molarity).
Molarity (mol/L) is calculated by dividing the number of moles by the volume of the solution in liters:
Molarity = number of moles / volume of solution = moles / liters.
Now, let's substitute the values into the equation:
Molarity = 0.185 g / 74.10 g/mol / 0.1 L
Now, calculate the molar concentration:
Molarity = 0.185 / 74.10 / 0.1 = 0.025 mol/L
Therefore, the molar concentration of calcium hydroxide in the solution is 0.025 mol/L.