ok this problem has made me crazy , 15 % is w\v ok , so i just the m1 , the mass of naoh i don't need the volume , so ill reformulate the problem again , I need the mass of naoh with conc.15% w/v in 176 g h2so4 ok

It still makes no sense to me. Here is the problem as I see it. I don't understand what the 15% has to do with the problem.

What is the mass of NaOH (notice I use caps since naoh means absolutely nothing) required to neutralize 176 g H2SO4.
2NaOH + H2SO4 ==> 2H2O + Na2SO4

moles H2SO4 = 176g/molar mass H2SO4 = ??
Convert to mols NaOH using the coefficients in the balanced equation.
moles NaOH = moles H2SO4 x (2 moles NaOH/1 mole H2SO4) = ??
Then g NaOH = moles NaOH x molar mass NaOH.

mole H2SO4 = 176/98 = 1.796
mole NaOH = 2*1.796 = 3.592
g NaOH = 3.592*40 = 143.7 g.

the problem requires the quantity of NaOH, this is what i don't understand what does it mean by quantity , the volume , the mass ,or the molar concentration ?? it must be the molar concen. of NaOH since i have to use all the things that are give to the exerc. including the 15 % concentration of NaOH

To solve this problem, you need to calculate the mass of sodium hydroxide (NaOH) with a concentration of 15% w/v in 176 g of sulfuric acid (H2SO4).

First, let's understand the given information:
- The concentration is stated as 15% w/v, which means that there is 15 grams of NaOH present in every 100 mL (or 100 grams) of solution.
- The mass of the sulfuric acid is given as 176 g.

To find the mass of NaOH, you can follow these steps:

Step 1: Calculate the volume of the solution.
Since you know the concentration is given as a percentage by weight/volume, you need to convert the given mass of H2SO4 into volume. To do this, you need to determine the density of H2SO4.
Density (d) is defined as mass (m) divided by volume (v): d = m/v.
You need to find the density of H2SO4, which can vary depending on its concentration. Once you have the density, you can calculate the volume of the given mass of H2SO4.
Alternatively, if the density is not provided, you can assume the density of 1.84 g/mL at room temperature (25°C).

Step 2: Calculate the volume of NaOH solution.
Since the concentration is given as 15% w/v, you need to determine how much NaOH is present in the given volume of the solution. To do this, calculate 15% of the volume calculated in Step 1.

Step 3: Calculate the mass of NaOH.
Multiply the volume of the NaOH solution obtained in Step 2 by its density (1 g/mL) to get the mass of NaOH.

Remember to convert your final answer to the proper units (grams) and round to an appropriate number of significant figures.

By following these steps, you should be able to find the mass of NaOH in 176 g of H2SO4 with a concentration of 15% w/v.