Is this right?

Balanced: 3 Mg(s) + 2 Al(NO3)3(aq) = 2 Al(s) + 3 Mg(NO3)2(aq)

Total Ionic Equation:
3 Mg(s) + 2 Al +3 (aq) + 6NO3 -1 (aq) = 2 Al(s) + 3 Mg+2 (aq) + 6NO3 -1 (aq)

Net Equation : 3 Mg(s) + 2 Al +3 (aq) = 2 Al(s) + 3 Mg+2 (aq)

yes, correct.

The balanced equation you provided is partially correct. However, there are some errors in the total ionic equation and net equation you wrote.

The correctly balanced equation is:

3 Mg(s) + 2 Al(NO3)3(aq) → 2 Al(s) + 3 Mg(NO3)2(aq)

Total Ionic Equation:

3 Mg(s) + 2 Al3+(aq) + 6 NO3-(aq) → 2 Al(s) + 3 Mg2+(aq) + 6 NO3-(aq)

Net Ionic Equation:

3 Mg(s) + 2 Al3+(aq) → 2 Al(s) + 3 Mg2+(aq)

In the net ionic equation, we exclude the spectator ions (ions that appear on both sides of the equation without undergoing a chemical change), which in this case are NO3-. Therefore, the net ionic equation only shows the species that participate in the chemical reaction.

Yes, the balanced equation you provided is correct:

Balanced: 3 Mg(s) + 2 Al(NO3)3(aq) = 2 Al(s) + 3 Mg(NO3)2(aq)

To check if the equation is balanced, you need to ensure that the number of each type of atom is the same on both sides of the equation. In this case, there are 3 magnesium (Mg) atoms and 2 aluminum (Al) atoms on both sides, as well as 6 nitrate (NO3) ions on both sides. Hence, the equation is balanced.

The total ionic equation and the net ionic equation you provided are also correct. The total ionic equation shows all the ions present in the reaction, while the net ionic equation only includes the species that participate in the reaction. In this case, the net ionic equation is formed by eliminating the spectator ions (the ions that do not change their oxidation state or do not participate in the reaction) from the total ionic equation.

Net Equation: 3 Mg(s) + 2 Al +3 (aq) = 2 Al(s) + 3 Mg+2 (aq)

Again, it is important to note that the net ionic equation only shows the species that are directly involved in the reaction.