Factor completely and then place the factors in the proper location on the grid.
4y2 + 25y + 6
Online "^" is used to indicate an exponent; x^2 = x squared.
Factor the end values into two factors each (4,1 or 2,2) and (6,1 or 3,2).
See which combination will sum to the middle value.
I cannot see your grid.
4y2 + 25y + 6
To factor the quadratic equation 4y^2 + 25y + 6, we need to find two binomials that multiply together to give us the original equation.
To do this, we will use a method called the "AC method" or "splitting the middle term."
1. Multiply the coefficient of the quadratic term (4) by the constant term (6). (4 * 6 = 24)
2. Now, we need to find two numbers that multiply together to give us 24 and also add up to the coefficient of the linear term (25).
These numbers are 1 and 24.
(1 * 24 = 24, 1 + 24 = 25)
3. Rewrite the middle term (25y) using these two numbers:
4y^2 + 1y + 24y + 6
4. Group the terms:
(4y^2 + 1y) + (24y + 6)
5. Factor out the greatest common factor from each group:
y(4y + 1) + 6(4y + 1)
6. Notice that both groups have a common factor of (4y + 1).
7. Factor out (4y + 1) from both groups:
(4y + 1)(y + 6)
Now, to place the factors in the proper location on the grid, you will need to provide more information about the grid. Please provide details or instructions regarding the grid, and I will be happy to assist you further.