you must prepare 300 mL of .750M NaBr solution using 2M NaBr stock solustion. how many mL of stock solution should you use?
mL x M = mL x M
To determine the volume of the stock solution needed, you can use the dilution formula:
C1V1 = C2V2
where:
C1 = initial concentration (2M)
V1 = volume of stock solution used
C2 = final concentration (0.750M)
V2 = final volume (300 mL)
Rearranging the formula, we have:
V1 = (C2 × V2) / C1
Substituting the values:
V1 = (0.750M × 300 mL) / 2M
V1 = 0.375 × 300 mL
V1 = 112.5 mL
Therefore, you should use 112.5 mL of the 2M NaBr stock solution to prepare 300 mL of a 0.750M NaBr solution.
To determine how many milliliters (mL) of the 2M NaBr stock solution should be used to prepare a 300 mL .750M NaBr solution, we can use the formula:
(M₁V₁) = (M₂V₂)
Where:
M₁ = concentration of stock solution
V₁ = volume of stock solution
M₂ = concentration of desired solution
V₂ = volume of desired solution
Let's assign the values:
M₁ = 2M (concentration of the stock solution)
V₁ = volume of stock solution (unknown)
M₂ = .750M (concentration of the desired solution)
V₂ = 300 mL (volume of the desired solution)
Plugging in the values into the formula, we have:
(2M)(V₁) = (.750M)(300 mL)
Now, we can solve for V₁:
2V₁ = (0.750)(300)
2V₁ = 225
V₁ = 225/2
V₁ = 112.5 mL
Therefore, approximately 112.5 mL of the 2M NaBr stock solution should be used to prepare a 300 mL .750M NaBr solution.