HOW MANY CALORIES ARE REQUIRED TO HEAT OF EACH OF THE FOLLOWING FROM 15 DEGREE CELSIUS TO 65 DEGREE CELSIUS?
A. 30 G OF Aluminum
b. 20 g of platinum
c. 35 g of water
heat= mass*specificheatcapacity*(changetemp)
how many calories are required to heat each of the following from 15⁰C to 65⁰C
To calculate the amount of calories required to heat a substance, we need to use the specific heat capacity equation:
Q = m * c * ΔT
where:
Q is the amount of heat energy (in calories),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in cal/g°C), and
ΔT is the change in temperature (in °C).
A. Aluminum:
The specific heat capacity of aluminum is 0.22 cal/g°C.
The mass of aluminum is 30 g.
The change in temperature is (65°C - 15°C) = 50°C.
Using the formula Q = m * c * ΔT, we can calculate the amount of calories:
Q = 30 g * 0.22 cal/g°C * 50°C
Q = 330 cal
So, it would require 330 calories to heat 30 g of aluminum from 15°C to 65°C.
B. Platinum:
The specific heat capacity of platinum is 0.036 cal/g°C.
The mass of platinum is 20 g.
The change in temperature is (65°C - 15°C) = 50°C.
Using the formula Q = m * c * ΔT, we can calculate the amount of calories:
Q = 20 g * 0.036 cal/g°C * 50°C
Q = 36 cal
So, it would require 36 calories to heat 20 g of platinum from 15°C to 65°C.
C. Water:
The specific heat capacity of water is 1 cal/g°C.
The mass of water is 35 g.
The change in temperature is (65°C - 15°C) = 50°C.
Using the formula Q = m * c * ΔT, we can calculate the amount of calories:
Q = 35 g * 1 cal/g°C * 50°C
Q = 1750 cal
So, it would require 1750 calories to heat 35 g of water from 15°C to 65°C.
To calculate the calories required to heat a substance, you need to use the specific heat capacity formula:
Q = m * c * ΔT
Where:
Q is the heat energy in calories
m is the mass of the substance in grams
c is the specific heat capacity of the substance in calories/gram °C
ΔT is the change in temperature in °C
Now, let's calculate the calories required for each substance:
A. Aluminum:
m = 30 g
c = 0.22 calories/gram °C (specific heat capacity of aluminum)
ΔT = 65°C - 15°C = 50°C
Q = 30 g * 0.22 cal/g°C * 50°C = 330 calories
Therefore, it would require 330 calories to heat 30 grams of aluminum from 15°C to 65°C.
B. Platinum:
m = 20 g
c = 0.13 calories/gram °C (specific heat capacity of platinum)
ΔT = 65°C - 15°C = 50°C
Q = 20 g * 0.13 cal/g°C * 50°C = 130 calories
Therefore, it would require 130 calories to heat 20 grams of platinum from 15°C to 65°C.
C. Water:
m = 35 g
c = 1 calorie/gram °C (specific heat capacity of water)
ΔT = 65°C - 15°C = 50°C
Q = 35 g * 1 cal/g°C * 50°C = 1750 calories
Therefore, it would require 1750 calories to heat 35 grams of water from 15°C to 65°C.