find f'(x) for the following:
f(x)= cos^5(4x-19)
I keep getting 20cos^4(4x-19)sin, but the answer is supposed to be
-20cos^4(4x-19)sin(4x-19). I can't seem to get there with derivatives

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  1. never mind. I figured it out. That is the correct anser, I didn't carry through with the derivitives.

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