The combustion of propane (C3H8)produces CO2 and H20: C3H8(g)+5O2(g) 3CO2(g)+4H2O(g) Calculate the mass, in grams, of H2O that will be produced if 2.5 mol of O2 is consumed.
follow steps 3 and 4:
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To calculate the mass of H2O produced, we need to determine the stoichiometric ratio between O2 and H2O in the balanced chemical equation.
The balanced chemical equation is:
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
From the equation, we can see that for every 5 moles of O2 consumed, 4 moles of H2O are produced.
Given that 2.5 moles of O2 is consumed, we can set up a proportion:
5 moles O2 / 4 moles H2O = 2.5 moles O2 / x moles H2O
Multiplying both sides of the equation by 4 and dividing by 5, we get:
(5/4) * 2.5 = x
x = 3.125
Therefore, 2.5 moles of O2 will produce 3.125 moles of H2O.
To calculate the mass of H2O, we need to use the molar mass of water (H2O). The molar mass of H2O is approximately 18 g/mol.
Mass of H2O = moles of H2O * molar mass of H2O
Mass of H2O = 3.125 moles * 18 g/mol
Mass of H2O = 56.25 g
Therefore, if 2.5 moles of O2 are consumed, the mass of H2O produced will be 56.25 grams.
To calculate the mass of H2O produced, you need to follow these steps:
1. Determine the balanced chemical equation for the combustion of propane.
The balanced equation is: C3H8(g) + 5O2(g) -> 3CO2(g) + 4H2O(g)
2. Find the stoichiometric ratio between O2 and H2O.
The stoichiometric ratio is the mole ratio between O2 and H2O in the balanced equation. From the equation, you can see that for every 5 moles of O2, 4 moles of H2O are produced.
3. Calculate the number of moles of H2O produced.
Since you are given 2.5 moles of O2, you can use the stoichiometric ratio from step 2 to calculate the number of moles of H2O produced.
2.5 moles O2 * (4 moles H2O / 5 moles O2) = 2 moles H2O
4. Determine the molar mass of H2O.
The molar mass of H2O is the sum of the atomic masses of its elements:
2(1.008 g/mol for hydrogen) + 16.00 g/mol for oxygen = 18.016 g/mol
5. Calculate the mass of H2O produced.
To find the mass of H2O produced, multiply the number of moles of H2O (from step 3) by the molar mass of H2O (from step 4).
2 moles H2O * 18.016 g/mol H2O = 36.032 g H2O
Therefore, if 2.5 moles of O2 is consumed, the mass of H2O produced is approximately 36.032 grams.