chemistry

The combustion of propane (C3H8)produces CO2 and H20: C3H8(g)+5O2(g) 3CO2(g)+4H2O(g) Calculate the mass, in grams, of H2O that will be produced if 2.5 mol of O2 is consumed.

asked by michelle
  1. You do mol×molar mass which is 2.5×18 and the answer is 45g. Hope this answered your question correctly:)

    posted by Jasmine

Respond to this Question

First Name

Your Response

Similar Questions

  1. chemistry

    The combustion of propane (C3H8)produces CO2 and H20: C3H8(g)+5O2(g) 3CO2(g)+4H2O(g) Calculate the mass, in grams, of H2O that will be produced if 2.5 mol of O2 is consumed.
  2. chem

    Consider the combustion of propane (C3H8) in the presence of oxygen: C3H8+5O2 => 3CO2+4H2O How many grams of O2 are required to react completely with 3 moles of propane?
  3. Chemistry

    Consider the combustion of propane (C3H8) in the presence of oxygen: C3H8+5O2 => 3CO2+4H2O How many grams of O2 are required to react completely with 3 moles of propane?
  4. Chemistry

    propane(C^3H^8)is used as a fuel. Propane is a type of hydrocarbon. Write a balanced equation for the combustion of propane in oxygen. Assume that the combustion is complete. Hydrocarbons (C and H compounds of which propane is
  5. chemistry

    What mass of propane (C3H8) is needed to produce 346g carbon dioxide in the following reaction? C3H8(g)+5O2(g)---> 3CO2(g) +4H2O(g) A. 115g C3H8 B. 1.86g C3H8 C. 5075g C3H8 D. 346g C3H8
  6. chemistry question

    What mass of propane (C3H8) is needed to produce 346 g carbon dioxide in the following reaction? C3H8(g) + 5O2(g) -> 3CO2(g) + 4H2O(g) A. 346 g C3H8 B. 115 g C3H8 C. 5075 g C3H8 D. 1.86 g C3H8
  7. Chem

    The combustion of propane (C3H8) produces CO2 and H2O: C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g) The reaction of 3.5 mol of O2 will produce ________ mol of H2O.
  8. Chemistry

    Oops I posted the right question but wrong answer options... What mass of propane (C3H8) is needed to produce 346g carbon dioxide in the following reaction? C3H8(g)+5O2(g)->3CO2(g)+4H2O(g) A. 346g C3H8 B. 115g C3H8 C. 5075g
  9. Chemistry

    Consider the burning of LPG (propane C3H8)which produces carbon dioxide (CO2) and water vapor (H2O). The balanced chemical equation involving the reaction is C3H8+5O2= 3CO2+4H2O Suppose 1.5 moles of C3H8 will be used, assume the
  10. Chemistry

    Propane, C3H8, is a common fuel gas. Use the following to calculate the grams of propane you would need to provide 369 kJ of heat. C3H8 (g) + 5O2 (g) --> 3CO2 (g)+ 4H2O (g) ; Delta H = -2043kJ

More Similar Questions