# URGENT! chemistry- percentage yield

heating an ore of antimony sulfide in the presence of iron gives th element antimony and iron(2) sulfide. when 15.0 antimony sulfide reacts with an excess of iron, 9.84 g antimony is produced. what is the percent yield of this reaction?

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1. You need to calculate the theoretical yield (Y) starting from 15.0 (I presume g) of antimony sulfide. In order to do this you need a balanced equation, so you need to insert symbols and balance:

iron + antimony sulfide -> antimony + iron(II)sulfide.

To calculate the theoretical yield find the number of moles of antimony sulfide in 15.0 g.

15.0 g/(Molar mass of antimony sulfide)

then calculate the theoretical number of moles of antimony formed using the balanced equation.

Y (theoretical yield) is then

Y=moles of antimony x molar mass of antimony.

percentage yield
= (9.84 g x 100)/Y

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