A water tower is filled with fresh water to a depth of 6.38 m. What is the water pressure at a depth of 3.96 m?
take a column of area A, height h.
The weight of that column is density*volume*g=density*Ah*g
= 1000kg/m^2*9.8N/kg*A*(3.96)
pressure= weight/A
I measured depth from the top, I assume the writer here had that in mind.
I'm confused about what A should be then? Is that what I'm solving for? I thought I was solving for pressure?
A cancels top and bottom
Top and Bottom??
To find the water pressure at a certain depth, you can use the formula:
Pressure = Density x Gravitational Acceleration x Height
The density of fresh water is approximately 1000 kg/m^3, and the gravitational acceleration is 9.8 m/s^2.
So, to find the water pressure at a depth of 3.96 m, plug in the values into the formula:
Pressure = 1000 kg/m^3 x 9.8 m/s^2 x 3.96 m
Simplifying this equation, we get:
Pressure = 39168 Pascal (Pa)
Therefore, the water pressure at a depth of 3.96 m is approximately 39168 Pa.