A water tower is filled with fresh water to a depth of 6.38 m. What is the water pressure at a depth of 3.96 m?

take a column of area A, height h.

The weight of that column is density*volume*g=density*Ah*g
= 1000kg/m^2*9.8N/kg*A*(3.96)

pressure= weight/A

I measured depth from the top, I assume the writer here had that in mind.

I'm confused about what A should be then? Is that what I'm solving for? I thought I was solving for pressure?

A cancels top and bottom

Top and Bottom??

To find the water pressure at a certain depth, you can use the formula:

Pressure = Density x Gravitational Acceleration x Height

The density of fresh water is approximately 1000 kg/m^3, and the gravitational acceleration is 9.8 m/s^2.

So, to find the water pressure at a depth of 3.96 m, plug in the values into the formula:

Pressure = 1000 kg/m^3 x 9.8 m/s^2 x 3.96 m

Simplifying this equation, we get:

Pressure = 39168 Pascal (Pa)

Therefore, the water pressure at a depth of 3.96 m is approximately 39168 Pa.