# Chemistry

Calculate the mass in g of aniline (C6H5NH2, Kb = 4.3 x 10-10) that must be added to 1.4 x 102 mL of 0.24 M (C6H5NH3)Cl solution in order to generate a buffer solution of pH 5.56. Give your answer to 2 significant figures.

Noclue...

1. 👍
2. 👎
3. 👁
4. ℹ️
5. 🚩
1. Use the Henderson-Hasselbalch equation.
Aniline is the base and aniline chloride is the acid.
pH = pKa + log [(base)/(acid)]
Show your work if you get stuck.

1. 👍
2. 👎
3. ℹ️
4. 🚩

## Similar Questions

2. ### chemistry

A 4.98 g sample of aniline (C6H5NH2, molar mass = 93.13 g/mol) was combusted in a bomb calorimeter with a heat capacity of 4.25 kJ/°C. If the temperature rose from 29.5°C to 69.8°C, determine the value of ΔH°comb for aniline.

3. ### Chem (Help!)

I really need help answering these questions. A sample of CO2 gas with a mass of 0.30 g is placed in a 250 mL container at 400 K. What is the pressure in atmospheres exerted by this gas? Before you can put the numbers into an

4. ### Chemistry- Empirical Formula

Aniline, consists of C, H, and N. Combustion of such compounds yields CO2, H2O, and N2. If the combustion of 9.71 mg of aniline yields 6.63 mg H2O and 1.46 mb N2, what is the empirical formula? What is the molecular formula of a

1. ### Chemistry

A solution of aniline(C6H5NH2, Kb=4.2x10^-10) has a pH of 8.69 at 25 Celsius. What was the initial concentration of aniline? I have so far don't know if it's right: *. [H3O]=10^-8.69=2x10^-9 * 4.2x10^-10=(2x10^-9)^2 / x

2. ### Chemistry

Given that Ka for HIO is 3.2 × 10-11 at 25 °C, what is the value of Kb for IO– at 25 °C? Then, Given that Kb for C6H5NH2 is 1.7 × 10-9 at 25 °C, what is the value of Ka for C6H5NH3 at 25 °C? I don't know where to start? Do

3. ### AP Chemistry

Which solution has the highest pH? 1. 0.1 M C6H5NH3Cl, Kb C6H5NH2 = 4.2 × 10−10 2. 0.1 M NH2(OH)2Cl, Kb NH2OH = 6.6 × 10−9 3. 0.1 M NaCl, Kb  zero 4. 0.1 M NH4Cl, Kb NH3 = 1.8 × 10−5 5. 0.1 M CH3NH3Cl, Kb CH3NH2 = 5.0 ×

4. ### Chemistry

How do I do this?? Calculate the pH at the equivalence point for the titration of 0.20 M aniline (C6H5NH2, Kb = 3.8 x 10-10) with 0.20 M HCl. [Hint: remember the dilution factor caused by addition of titrant to the aniline

1. ### Chemistry

The equilibrium constant for the reaction of the weak base aniline is Kb = 4.3e-10. C6H5NH2 (aq) + H2O (l) --> C6H5NH3+ (aq) + OH- (aq). Calculate ΔG at 298 K when [C6H5NH2] = 0.250 M, [C6H5NH3+] = 1.0E-5 M, [OH-] = 0.000480 M i

2. ### science

Written out, would the reaction between anihiline [C6H5NH2] and perchloric acid look like this: C6H5NH2 + HClO4 -> C6H5ClO4 + HNH2 ? The NH2 group on aniline is basic. It takes on a H^+ from HClO4 and forms the salt. The salt is

3. ### PHYSICS

A mass of 0.5kg is attached to a spring. The mass is then displaced from its equilibrium position by 5cm and released. Its speed as it passes the equilibrium position is 50cm per seconds. a) Calculate the spring constant of the

4. ### Chemisttry

A 100.0-mL sample of 0.250 M aniline (C6H5NH2) is titrated with 0.500 M HCl. What is the pH at the equivalence point?