algebra
I have a problem with break even analysis? the question is I'm trying to find the cost between 2 businesses to care for my lawn. The one company has an initial fee of $200+$50an hour for labor cost and the second company has an initial cost of $300+$25an hour for labor cost. If h represents the #of labor hours and c represents the total cost it say wright the total cost equation for each. I got $200+$50h=C
$300+$25h=c
then it says to solve the equation for total cost of lawn care by using desired technique:substitution, elimination, or graphing.
Am I on the right track
asked by
Sylvia

yes, on the right track.
posted by bobpursley
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did I solve the problem correctly? c=$200+$50h c=$300+$25h is the answer c=$250 c=$325 Do all I have to do to this equation is to add them to get the total cost of labor with h=labor per hour and c=cost or do I have to solve it in