y^3- 7y^2+ 8y -13 y=2
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To solve the equation y^3 - 7y^2 + 8y - 13y = 2, you need to substitute the value of y in the equation and find the result.
1. Write the equation: y^3 - 7y^2 + 8y - 13y = 2
2. Substitute y = 2 in the equation:
(2)^3 - 7(2)^2 + 8(2) - 13(2) = 2
8 - 7(4) + 16 - 26 = 2
8 - 28 + 16 - 26 = 2
-4 = 2
The result of this substitution is -4 = 2, which is not true. Therefore, the value of y = 2 does not satisfy the equation.
To find the value of y when y^3 - 7y^2 + 8y - 13 equals 2, we need to substitute y = 2 into the equation and solve for it. Here's how:
1. Replace every instance of y in the equation with 2:
(2)^3 - 7(2)^2 + 8(2) - 13 = 2
2. Simplify the equation:
8 - 7(4) + 16 - 13 = 2
8 - 28 + 16 - 13 = 2
-5 = 2
Since -5 does not equal 2, the equation is not true when y = 2. Therefore, there is no solution for this particular equation.