11. The charged plates of a parallel plate capacitor each have a charge density of 3 x 10-3 C/m2. What is the electric field E between the plates?
To find the electric field E between the plates of a parallel plate capacitor, you can use the equation:
E = σ/ε₀
Where:
- E represents the electric field strength
- σ represents the charge density (in C/m²)
- ε₀ represents the electric constant (ε₀ ≈ 8.85 x 10⁻¹² C²/N·m²)
In this case, the given charge density is 3 x 10⁻³ C/m². So we can substitute this value into the equation:
E = (3 x 10⁻³ C/m²) / (8.85 x 10⁻¹² C²/N·m²)
Now we can solve for E:
E ≈ 3.39 x 10⁹ N/C
Therefore, the electric field E between the plates of the parallel plate capacitor is approximately 3.39 x 10⁹ N/C.