Two rectangles are similar. One has a length of 10 cm and a width of 8 cm, and the other has a width of 7 cm. Find the length of the second triangle. Round to the nearest tenth if necessary.
I got 8.8 cm. I made a proportion 8/10=7/x and that's how I got 8.8. Is this right?
Yup (if you're find the length of the second RECTANGLE).
To find the length of the second rectangle, you correctly set up a proportion based on the similarity of the two rectangles.
The proportion you set up is: 8/10 = 7/x.
To solve this proportion, you can cross-multiply and then solve for x.
Cross-multiplying gives you: 8x = 7 * 10.
Simplifying further, you have: 8x = 70.
To isolate x, divide both sides of the equation by 8: x = 70/8.
Evaluating the division, you get: x ≈ 8.75.
Therefore, the length of the second rectangle is approximately 8.75 cm, rounded to the nearest tenth.
So, your answer of 8.8 cm is correct. Good job!