Determinne the amount of Dextrose and NaCl in 500ml of 5% DNS. (The solution is 5% in regards to dextrose and 0.9% in regards to NACl.)
This is where those crazy solution concentrations in medicine come in, you just can not say percent, you have to state the basis. Commonly, (in idiot medical terms), these are w/v. So I assume you are using w/v
.05 w/v or with 500ml, then you have 25g sugar, and 4.5g salt
I have never understood why w/v is used, I guess since it eliminates density, it is easier, afterall, who wants to worry with density?
To determine the amount of Dextrose and NaCl in 500ml of 5% DNS (Dextrose Normal Saline), you need to understand how percentage solutions are calculated and use that information to determine the quantities.
First, let's break down the information given:
- The solution is 5% DNS, which means it is 5% dextrose and 0.9% NaCl.
- We have a total volume of 500ml.
To determine the amount of dextrose, you need to calculate 5% of the total volume (500ml), as 5% represents the concentration of dextrose in the solution.
Calculation for Dextrose:
Amount of Dextrose (in ml) = 5% of the total volume (in ml)
Amount of Dextrose = (5/100) * 500ml
Amount of Dextrose = 0.05 * 500ml
Amount of Dextrose = 25ml
Therefore, there are 25ml of Dextrose in 500ml of 5% DNS.
Now, let's move on to calculating the amount of NaCl. We're given that the solution is 0.9% NaCl.
Calculation for NaCl:
Amount of NaCl (in ml) = 0.9% of the total volume (in ml)
Amount of NaCl = (0.9/100) * 500ml
Amount of NaCl = 0.009 * 500ml
Amount of NaCl = 4.5ml
Therefore, there are 4.5ml of NaCl in 500ml of 5% DNS.
To summarize, in 500ml of 5% DNS solution, there are 25ml of Dextrose and 4.5ml of NaCl.