a skater with an initial speed of 7.60m/s is gliding across the ice. air resistance is negligible. (a)the coefficient of kinetic friction between the ice and the skate blades is 0.100. find the deceleration caused by kinetic friction. (b)how far will the skater travel before coming to rest?

can anyone please give me some hints to do it? THANKS A LOT!

i don't understand how you get this part..a = F/M = 0.1 g = 0.98 m/s^2

To solve this problem, you can use the following steps:

(a) To find the deceleration caused by kinetic friction, you can use the equation:

Frictional force (Fk) = coefficient of kinetic friction (μk) * normal force (N)

The normal force (N) is equal to the weight (mg), where m is the mass of the skater and g is the acceleration due to gravity.

Once you have the frictional force, you can use Newton's second law (F = ma) to find the deceleration (a):

Frictional force (Fk) = mass (m) * deceleration (a)

(b) To determine how far the skater will travel before coming to rest, you can use the equation:

Distance = (initial velocity^2) / (2 * deceleration)

By substituting the initial velocity and deceleration found in part (a) into this equation, you can calculate the distance.

These steps should help you solve the problem. Let me know if you need further assistance with any of the calculations!

Sure! I can provide some hints to help you solve the problem:

(a) To find the deceleration caused by kinetic friction, you need to use the equation:

F_friction = μ_k * N,

where F_friction is the force of friction, μ_k is the coefficient of kinetic friction, and N is the normal force. The normal force is equal to the weight of the skater, which can be calculated using the equation:

N = m * g,

where m is the mass of the skater and g is the acceleration due to gravity (approximately 9.8 m/s^2).

(b) To determine how far the skater will travel before coming to rest, you can use the equation:

v^2 = u^2 + 2as,

where v is the final speed (which is 0 m/s since the skater comes to rest), u is the initial speed (7.60 m/s), a is the acceleration due to kinetic friction (which you can calculate in part a), and s is the distance traveled.

I hope these hints help you solve the problem! Let me know if you need any further assistance.

If the kinetic friction coeffient is 0.1, the force that is opposig motion is (F = 0.1 * M g).

(a) The deceleration rate is therefore
a = F/M = 0.1 g = 0.98 m/s^2

(b) The time to come to rest, T, is given by
a T = 7.6 m/s.
Solve for T