# Physics

In a "worst-case" design scenario, a 2000-{\rm kg} elevator with broken cables is falling at 4.00 {\rm m/s} when it first contacts a cushioning spring at the bottom of the shaft. The spring is supposed to stop the elevator, compressing 2.00 {\rm m} as it does so. During the motion a safety clamp applies a constant 17000-{\rm N} frictional force to the elevator.

What is the speed of the elevator after it has moved downward 1.00 {\rm m} from the point where it first contacts a spring?

1. 👍 0
2. 👎 0
3. 👁 1,096
1. 3.46 m/s

1. 👍 0
2. 👎 0
2. conservation of energy.
KE + PE --> Wf + PEspring
.5mv^2 + mgh = 17000*1 + .5kx^2
v = 3.65

1. 👍 1
2. 👎 0

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