4. What is the electric potential at the surface of a gold atom’s nucleus, which is assumed to be spherical? The radius of a gold nucleus is 6.6 x 10-15 meters and the atomic number of gold is 79.

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  1. V=kq/r q= 79*(-e)/r where e is the charge on an electron.

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  2. 1.72×10^-7

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  3. V= kq/r ---------1.

    k= 9*(10^9)
    r= 6.6*(10^-15)m
    q= ne = 79* 1.6*(10^-19)C

    put these values in eq. 1.

    V= 172.36 * 10^5
    V= 1.7236 * 10^7 = (1.724 * 10^7)V

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