What current would flow in an ordinary 115 V household circuit, if a 1430 W hair drier and a 1000 W microwave oven were operating simultaneously on this line?How much current would the hair drier and microwave from the previous question draw, if they were connected to the 115 V line in series?
Operated simultaneously and in parallel, the total power drawn would be 1430 + 1000 = 2430 W
2430 W = 115V * (total current)
Solve for total current.
In series, neither unit would operate at full voltage and power. You need to determine what the resistance of each appliance is. That will presumably be independent of applied voltage.
V^2/R(drier) = 1430 W (rated power)
Using V = 115 V,
R(drier) = 9.25 ohms
V^2/R(oven) = 1000W
R(oven) = 13.23 ohm
I(series circuit) = V/(9.25+13.23)
= 115/22.48 ohms
(much less than the parallel case)
To calculate the current flowing through a circuit, you can use Ohm's Law, which states that current (I) equals power (P) divided by voltage (V):
I = P / V
For the first question, we have two devices operating simultaneously: a hair drier with a power rating of 1430 W and a microwave oven with a power rating of 1000 W. The voltage of the household circuit is given as 115 V.
To find the total current flowing through the circuit, we need to calculate the total power consumed by the devices:
Total Power = Power Hair Drier + Power Microwave Oven
= 1430 W + 1000 W
= 2430 W
Substituting the values into Ohm's Law, we find:
Total Current = Total Power / Voltage
= 2430 W / 115 V
≈ 21.13 A
Therefore, the total current flowing through the circuit would be approximately 21.13 Amperes.
For the second question, if the hair drier and microwave oven were connected in series on the same 115 V line, the current would be the same throughout the circuit. In a series circuit, the current flowing through each component is the same. Hence, the current drawn by both devices would be the same as the total current calculated in the previous answer, which is approximately 21.13 Amperes.