Chemistry

At 1473K the equilibrium constant for the reaction H2(g) + Cl2(g) <--------> 2HCl(g)
Kc = 2.5*10^4. What would be the equilibrium concentration of HCL if the initial concentrations of H2 and Cl2 were 0.1840M and 0.1918M. I got 29.7 but was told it was wrong

asked by Jude
  1. ..........H2 + Cl2 ==> 2HCl
    begin..0.1840 0.1918...0
    change.....-x...-x.......+2x
    final.0.1840-x..0.1918-x...2x
    Substitute into Kc and solve for x, then multiply by 2 for HCl.

    posted by DrBob222

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