What is the pH of a 1.00 molar solution of NaNO3(aq)?The Ka for nitric is 0.0007.show all calculations
I am having a tough time believing that the Ka for HNO3 is 7E-4.
To find the pH of a 1.00 molar solution of NaNO3(aq), we need to consider the dissociation of NaNO3 in water. NaNO3 breaks down into its constituent ions, Na+ and NO3-, in solution.
Since Na+ is a spectator ion (does not affect pH), we only need to consider the NO3- ions. NO3- can react with water to form nitric acid (HNO3), which partially dissociates into H+ and NO3- ions.
Given that the Ka for nitric acid is 0.0007, we can use this information to calculate the concentration of H+ ions and, subsequently, the pH of the solution.
Step 1: Write the chemical equation for the dissociation of nitric acid in water:
HNO3(aq) ⇌ H+(aq) + NO3-(aq)
Step 2: Write the equilibrium expression for the dissociation of nitric acid:
Ka = [H+][NO3-] / [HNO3]
Step 3: Since we know that [NO3-] = 1.00 M (from the NaNO3 solution), we can rewrite the equation as:
Ka = [H+](1.00 M) / [HNO3]
Step 4: Rearrange the equation to solve for [H+]:
[H+] = Ka * [HNO3] / (1.00 M)
Step 5: Substitute the given value for Ka (0.0007) and the concentration of HNO3 (1.00 M) into the equation:
[H+] = (0.0007) * (1.00 M) / (1.00 M)
Step 6: Simplify the equation:
[H+] = 0.0007 M
Step 7: Calculate the pH using the equation:
pH = -log[H+]
Step 8: Substitute the value of [H+] (0.0007 M) into the equation:
pH = -log(0.0007)
Step 9: Calculate the pH:
pH ≈ 3.15
Therefore, the pH of the 1.00 molar solution of NaNO3(aq) is approximately 3.15.
To determine the pH of a 1.00 molar solution of NaNO3(aq), we first need to understand the properties of the compound NaNO3. NaNO3 is a salt compound composed of sodium ions (Na+) and nitrate ions (NO3-). Since it is a salt, it dissociates completely in water, meaning it completely breaks apart into its constituent ions.
To find the pH of the solution, we need to consider the acidic or basic nature of the ions produced when NaNO3 dissociates. In this case, Na+ is a neutral cation (it does not affect the pH), while NO3- is a neutral anion (it also does not affect the pH). Therefore, the pH of the resulting solution will be neutral.
The pH of a neutral solution is typically defined as 7. Hence, the pH of a 1.00 molar solution of NaNO3(aq) will be 7.
The given Ka value of 0.0007 for nitric acid (HNO3) is not relevant to finding the pH of a solution of NaNO3 because sodium nitrate does not react with water to produce hydronium ions (H3O+).
In summary:
- The pH of a 1.00 molar solution of NaNO3(aq) is 7.
- The given Ka value (0.0007) for HNO3 is not used to find the pH of NaNO3 solution.