2 rectangles are similar. Which is a correct proprtion for corresponding sides?

For one rectangle, the length is 12 and the width is 4. The other rectangle has 8 as the width and x as the length. I think it's 4/12=x/8. Is this right?

"Width" is the smaller of the two dimensions of the rectangle. Since the width has doubled from 4 to 8 for the "other" rectangle, the length must double also, to 24.

So the proportion is 12/4=x/8?

Is the proportion 12/4=x/8?

No. It is 2:1

I forgot to post the answer choices

a 12/8=x/4
b 12/4=x/8
c 12/4=x/20
d 4/12=x/8

Yes, you are on the right track! To determine the correct proportion for corresponding sides of similar rectangles, we can set up a ratio between the corresponding side lengths.

For the first rectangle, we have a length of 12 and a width of 4.
For the second rectangle, we have a width of 8 and an unknown length denoted as 'x'.

To find the correct proportion for corresponding sides, we can set up a ratio by comparing the corresponding side lengths of the two rectangles:

Length of first rectangle : Length of second rectangle
Width of first rectangle : Width of second rectangle

So, the correct proportion can be set up as: 12/x = 4/8.

To simplify this proportion, we can cross-multiply:

(12)(8) = (4)(x)

96 = 4x

Now, solve for x:

96/4 = x

x = 24

Hence, the correct proportion for the corresponding sides is 12/24 = 4/8, or alternatively, 1/2 = 1/2.

Therefore, your initial equation 4/12 = x/8 is correct, and x = 24 is the solution to the proportion.

b. x (the length of the "other" triangle) = (8/4) x 12 = 24