What volume of a 0.34M MgCL2 solution is required to make 250ml of a 0.10M solution by dilution?

mL x M = mL x M

To find out the volume of the 0.34M MgCl2 solution required for dilution, we need to use the formula for dilution:

C1V1 = C2V2

where:
C1 = initial concentration of the solution (0.34M)
V1 = initial volume of the solution (unknown)
C2 = final concentration of the solution (0.10M)
V2 = final volume of the solution (250ml)

Rearranging the formula, we have:

V1 = (C2 * V2) / C1

Now let's substitute the given values:

V1 = (0.10M * 250ml) / 0.34M

Simplifying this equation, we get:

V1 = (0.10 * 250) / 0.34
= 25 / 0.34
≈ 73.53 ml

Therefore, approximately 73.53 ml of the 0.34M MgCl2 solution is required to make 250 ml of a 0.10M solution by dilution.