A student increases the temperature of a 200 cm3 balloon from 60°C to 180°C. What will the new volume of the balloon be? (Be careful with units.)

(V1/T1)=(V2/T2)

Remember T must be in Kelvin.

To find the new volume of the balloon, we can use the combined gas law, which states that the ratio of the initial and final volumes of a gas is equal to the ratio of the initial and final temperatures, assuming the pressure remains constant. The formula for the combined gas law is:

(V1 / T1) = (V2 / T2)

where:
V1 = initial volume
T1 = initial temperature
V2 = final volume (what we want to find)
T2 = final temperature

Let's plug in the given values:

V1 = 200 cm3 (initial volume)
T1 = 60°C (initial temperature)
T2 = 180°C (final temperature)

Now, we can rearrange the formula to solve for V2:

V2 = (V1 x T2) / T1

Substituting the values we have:

V2 = (200 cm3 x 180°C) / 60°C

Now, we need to take care of the units. First, let's convert the initial volume from cm3 to a more common unit like liters (L). Since 1 L is equivalent to 1000 cm3, we divide the initial volume by 1000:

V1 = 200 cm3 / 1000 = 0.2 L

Next, we perform the calculation for the new volume:

V2 = (0.2 L x 180°C) / 60°C

Now, we simplify the equation:

V2 = 0.6 L

Therefore, the new volume of the balloon will be 0.6 liters.