physics

A projectile is launched with a speed of 41 m/s at an angle of 55° above the horizontal. Use conservation of energy to find the maximum height reached by the projectile during its flight.

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  1. Maximum height is achieved when the vertical velocity component, V sin 55 = 0

    The kinetic energy loss at that time, which is due to the vertical component only, equals the potential energy gain.

    (M/2) (Vsin55)^2 = M g H

    H = (Vsin55)^2/(2g)

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