Continue from the above. If a 10 ohm resistor is connected in the secondary, the current in the secondary is____ A (give your answer in number only, no unit)
I would drop the class, or get a lawyer.
This is a ridiculous statement: give your answer in number only, no unit.
If you calculated 1500mAmps, is 1500, 1.5 or what the correct response? Without units, numbers in physical science have no meaning, and this is pretty basic to understanding physics. I am surprised your professor seems to have forgotten this.
To determine the current in the secondary, we need to know the turns ratio and the current in the primary. The turns ratio (TR) of a transformer is the ratio of the number of turns in the secondary winding to the number of turns in the primary winding.
Let's assume the turns ratio is given as TS/TP, where TS is the number of turns in the secondary winding and TP is the number of turns in the primary winding. Without this information, it's not possible to calculate the current in the secondary.
However, if we assume that the turns ratio is 1 (meaning both windings have the same number of turns), we can use the formula for calculating the current in the secondary:
Is = Ip * (Np/Ns)
Where:
Is is the current in the secondary winding
Ip is the current in the primary winding
Np is the number of turns in the primary winding
Ns is the number of turns in the secondary winding
Since the turns ratio is equal to 1, Np = Ns, so the formula simplifies to:
Is = Ip
Therefore, if a 10-ohm resistor is connected in the secondary, the current in the secondary would be 10 A (amperes) assuming the turns ratio is 1.
Remember, this calculation is based on the assumption of a turns ratio of 1. However, in real-world scenarios, the turns ratio may be different, so it's important to know the actual turns ratio to get an accurate calculation.