A car traveling at 26 m/s undergoes a constant decleration of 12 m/s^2. About how long di=oes it take the car to come to a stop?
Vf=Vi+at
Vi=26m/s, Vf=0, a= 12m/s^2
To find the time it takes for the car to come to a stop, we can use the formula:
v = u + at
where
v = final velocity (which is 0 m/s, as the car comes to a stop)
u = initial velocity (26 m/s)
a = acceleration (12 m/s^2)
t = time
Rearranging the formula to solve for t, we have:
t = (v - u) / a
Substituting the given values, we can calculate the time it takes for the car to stop:
t = (0 - 26) / -12
Simplifying the equation:
t = -26 / -12
t = 2.17 seconds (rounded to two decimal places)
Therefore, it takes approximately 2.17 seconds for the car to come to a stop.