Chris has $3.85 in dimes and quarters. There are 25 coins in all. How many of each type of coin does he have?
If d represents the number of dimes and q represents the number of quarters, what two equations describe the problem?
Let x = # of dimes and Y = # of quarters.
10x + 25y = 3.85
x = 2/5y
Substitute 2/5y for x in first equation and solve for y. Insert that value into the second equation and solve for x. Check by inserting both values into the second equation.
the two equation is
0.10+0.25=3.85
x-y=25
To solve this problem, we can set up two equations based on the given information:
1. The total value of the coins: 0.10d + 0.25q = 3.85 (since the value of a dime is $0.10 and the value of a quarter is $0.25)
2. The total number of coins: d + q = 25 (since there are 25 coins in total)
These two equations describe the problem.
To solve this problem, we need to set up a system of equations based on the given information.
Let's start by using the given variables: d represents the number of dimes and q represents the number of quarters.
The first equation is based on the given total value of the coins: Chris has a total of $3.85 in dimes and quarters. Since the value of a dime is $0.10 and the value of a quarter is $0.25, we can write the equation as:
0.10d + 0.25q = 3.85
The second equation represents the total number of coins. We know that there are 25 coins in total, so the equation can be written as:
d + q = 25
Therefore, the two equations that describe the problem are:
0.10d + 0.25q = 3.85
d + q = 25