Solve esch system by substitution.

3c+2d=2
d=4

I am not sure what "Solve each system" means, but I would assume with the given information that you need to solve for "c", then solve for "d" with the answer to "c". To do that, your equation would look like this....

3c+2(4) = 2
3c+8 = 2
3c = 2-8
3c = -6
c = -6/3
c = -2

THEN

3(-2)+2d = 2
-6+2d = 2
2d = 2+6
2d = 8
d = 8/2
d = 4

I really do hope this helps.

To solve the system of equations by substitution, we will substitute the value of "d" from the second equation into the first equation.

Given equations:
1) 3c + 2d = 2
2) d = 4

We will substitute the value of "d" from the second equation (d = 4) into the first equation (3c + 2d = 2):

1) 3c + 2(4) = 2

Now, we solve this equation to find the value of "c".

1) 3c + 8 = 2

Subtract 8 from both sides:

1) 3c = 2 - 8
3c = -6

Divide both sides by 3:

1) c = -6/3
c = -2

Therefore, the solution to the system of equations is c = -2 and d = 4.