What is the percent composition of O in C8H8O3
(atomic mass O/molar mass C8H8O)*100 = ??
To determine the percent composition of oxygen (O) in a compound, you need to know the chemical formula of the compound and the molar mass of each element present in it.
In the given compound C8H8O3 (ethyl acetoacetate), it contains carbon (C), hydrogen (H), and oxygen (O). We will calculate the percent composition of oxygen.
Step 1: Find the molar mass of C8H8O3.
The molar mass of carbon (C) is approximately 12.01 g/mol.
The molar mass of hydrogen (H) is approximately 1.01 g/mol.
The molar mass of oxygen (O) is approximately 16.00 g/mol.
Molar mass of C8H8O3 = (8 * molar mass of C) + (8 * molar mass of H) + (3 * molar mass of O)
Molar mass of C8H8O3 = (8 * 12.01 g/mol) + (8 * 1.01 g/mol) + (3 * 16.00 g/mol)
Molar mass of C8H8O3 = 104.08 g/mol + 8.08 g/mol + 48.00 g/mol
Molar mass of C8H8O3 = 160.16 g/mol
Step 2: Calculate the percent composition of oxygen.
The percent composition of oxygen (O) can be calculated using the following formula:
Percent composition of O = (Number of O atoms * Molar mass of O) / Molar mass of C8H8O3
In this case, there are 3 oxygen atoms, and the molar mass of oxygen is approximately 16.00 g/mol.
Percent composition of O = (3 * 16.00 g/mol) / 160.16 g/mol
Percent composition of O = 48.00 g/mol / 160.16 g/mol
Percent composition of O = 0.2998
Now, to express it as a percentage, we multiply by 100:
Percent composition of O = 0.2998 * 100
Percent composition of O ≈ 29.98%
Therefore, the percent composition of oxygen (O) in C8H8O3 is approximately 29.98%.