A sailor strikes the side of her ship just below the waterline. She hears the echo of the sound reflected from the ocean floor directly below 2.00 s later. How deep is the ocean at this point? (Assume the velocity of sound in water is 1560 m/s, and enter your answer in meters; if you think the answer is 1000 m enter 1000.)

No clue how to do this.

2.00 s is the round trip tinme for the sound. She must have very good ears, unless she is using sonar equipment.

Vsound*(2.00 s) = 2*(depth)
= 3120 m
depth = 1560 m

enter 1560

To determine the depth of the ocean at the point where the sailor struck the side of her ship, we can use the equation for distance:

Distance = Velocity × Time

In this case, the distance represents the round-trip distance traveled by the sound signal, which is twice the depth of the ocean. The velocity of sound in water is given as 1560 m/s.

Let's break down the problem step by step:

1. Calculate the time it takes for the sound to travel back and forth between the ship and the ocean floor. The time given is 2.00 s.

2. Divide the round-trip time by 2 to find the time it takes for the sound to travel one way:

Time = 2.00 s /2 = 1.00 s

3. Now, we can substitute the given values into the equation for distance:

Distance = Velocity × Time
= 1560 m/s × 1.00 s
= 1560 m

4. However, remember that the distance calculated is the round-trip distance. Therefore, we need to divide the distance by 2 to find the actual depth of the ocean at that point:

Depth = Distance / 2
= 1560 m / 2
= 780 m

So, the depth of the ocean at the point where the sailor struck the ship is 780 meters.