# Chemistry

When 100mL of 1.00 M Ba (NO3)2 and 100 mL of 1.00 M Na2SO4, both at 25 degrees celsius, are mixed in a constant pressure calorimeter, a white precipitate is formed and the temperature rises to 28.1 degrees celsius.

A. What is the precipitate?
B. If all of the heat is absorbed by the solvent (water), what is the molar enthalpy change for the reaction.
(s for water = 4.18 J/g.C)

I really want to understand this problem so if someone could show me step by step I would really appreciate it so much!

1. 👍 0
2. 👎 0
3. 👁 327
1. A. Here is a simplified list of the solubility rules. You can find the material that ppts by studying this list.
http://www.files.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html

B. How much heat is absorbed by the water? That is q = heat absorbed = mass H2O x specific heat water x delta T. How many moles of the ppt do you have. (hint: Write the equation an balance it to find moles ppt). Then deltaH q/mol ppt.

Post your work if you get stuck.

1. 👍 0
2. 👎 0
2. So for part A i balanced the equation to:
Ba(NO3)2 + Na2 -> Ba(SO4) + 2Na(NO3)
then I got: (NO3)2 + Na2 -> 2NaNO3 does that mean 2NaNO3 is the precipitate?

For part B I got q= 233.5 J
and now I'm stuck lol

1. 👍 0
2. 👎 0
3. A. No, it doesn't mean NaNO3 is the ppt. You didn't read the table in the link I gave you. That link tells you that sulfates are soluble EXCEPT for (see #4 in the list).
Ba(NO3)2(aq) + Na2SO4(aq) ==> BaSO4(s) + 2NaNO3(aq).

B. 233.5 is not right.I don't know what show your work means to you but it doesn't mean to show the answer only. I'm headed to bed and I don't have time to wait around while we go through this so the problem follows:
mass x specific heat x delta T
200 g H2O x 4.18 x (28.1-25) = ?? = q
delta H/mol = q/mol = q/0.1 = ??

1. 👍 0
2. 👎 0

## Similar Questions

1. ### Organic Chemistry

The solubility of a compound is 59g per 100mL in boiling methanol and 30g per 100mL in cold methanol, whereas its solubility in water is 7.2g per 100mL at 95C and 0.22g per 100mL at 2C. Which solvent would be better for

2. ### General Chemistry

A student dissolved 4.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution and then diluted it with water to give 275. mL of a final solution. How many grams of NO3- ion are

3. ### Chemistry

Barium sulfate, BaSO4 is made by the following reaction. Ba(NO3)2(aq) + Na2SO4(aq)----> BaSO4(s) + 2NaNO3(aq) An experiment was begun with 91.77 g of Ba(NO3)2 and an excess of Na2SO4. After collecting and drying the product, 62.3

4. ### science

Na2So4+Hg(NO3)2 balance equation and find the spectator ion

1. ### Chemistry

how do u complete these questions? 2HCI(aq)+Pb(NO3)2(aq)---> 2HI(aq)+K2SO3(s)---> Pb(NO3)2(aq)+2KCI(aq)---> Ba(NO3)2(aq)+Na2SO4(aq)---> K2CO3(aq)+Ba(NO3)2(aq)---> HCI(aq)+AgNO3(aq)--->

2. ### Chemistry

Ba(NO3)2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaNO3(aq) An experiment was begun with 75.00 g of Ba(NO3)2 and an excess of Na2SO4. After collecting and drying the product, 64.45 g of BaSO4 was obtained. Calculate the theoretical yield

3. ### Chem

the solubility of a compound is 59g per 100 mL in boiling methanol and 30g per 100mL in cold methanol, whereas its solubility in water is 7.2g per 100 mL at 95 C and .22g per 100mL at 2C. Which solvent would be better for

4. ### Chemistry

A thoroughly dried 1.281g sample of Na2SO4 is exposed to the atmosphere and found to gain 0.383g in mass. What is the percent, by mass, of Na2SO4*10 H2O in the resulting mixture of anhydrous Na2SO4 and the decahydrate

1. ### Chem

Determine the number of moles of N atoms in 43.5 g of Mg(NO3)2. Textbook answer: 1.43 mol N My answer: 43.5 g Mg(NO3)x x (1 mol Mg(NO3)2/148.313 g Mg(NO3)2) x (2 mol N/1 mol Mg(NO3)2) = .293 Can tell me where i went wrong?

2. ### chemistry

The solubility of barium nitrate at 100°C is 34 g/100 g of H2O and at 0°C is 5.0 g/100g of H2O. If you start with 100 g of Ba(NO3)2 and make a saturated solution in water at 100°C, how much water is required? If the saturated

3. ### Chemistry

Below are the formulas of some hydrates. what is the mole ratio of salt to water? Hydrate Na2SO4.10H2O Co(NO3)2.6H2O Mo(NO3)2.5H2O CaSO4.2H2O (CaSO4)2.H2) Thankk you

4. ### Chemistry

Barium sulfate forms as a precipitate in the following reaction: Ba(NO3)2 (aq) + Na2SO4 (aq) -> BaSO4 (s) + 2NaNo3 (aq) When 35.0g of Ba(nO3)s is reacted with excess Na2SO4, 29.8g of BaSO4 is recovered by the chemist. a) Calculate