I need some help with this specific question. In a computer catalog, a computer monitor is listed as being 19 inches. This distance is the
diagonal distance across the screen. If the screen measures 10 inches in height, what is the
actual width of the screen to the nearest inch?
* I'd appreciate if I not only got an answer but an explanation too. Thanks :]
But how would you do it using
A^2 + B^2 = C^2 ?
To determine the actual width of the screen to the nearest inch, we can use the Pythagorean theorem.
The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, we can consider the height of the screen as one side of a right-angled triangle, and the width (which we want to find) as the other side. The diagonal distance across the screen is the hypotenuse.
So, we have:
Height of the screen = 10 inches
Diagonal distance across the screen = 19 inches
Let's label the width of the screen as 'w' (in inches).
Using the Pythagorean theorem, we can set up the following equation:
height^2 + width^2 = diagonal^2
10^2 + w^2 = 19^2
Simplifying the equation:
100 + w^2 = 361
Now, we can solve for 'w' by subtracting 100 from both sides:
w^2 = 361 - 100
w^2 = 261
To find the width, we need to take the square root of both sides:
w = √261
Rounding the square root of 261 to the nearest whole number:
w ≈ 16
Therefore, to the nearest inch, the actual width of the screen is approximately 16 inches.
Use the Pythagorean theorem?
d^2=h^2+w^2
19^2=10^2+w^2
Lord. It is the same thing. Letters don't matter.
diagonal^2=height^2 + width^2