how much of a 0.225 M KCl solution contains 55.8g of KCl
How many moles is 55.8 g. moles = grams/molar mass.
What is the definition of M?
M = moles/L
Substitute for M and moles; solve for L.
To find out how much of a 0.225 M KCl solution contains 55.8 grams of KCl, you need to use the formula:
moles = mass / molar mass
First, find the molar mass of KCl. The molar mass of K (potassium) is 39.1 g/mol, and the molar mass of Cl (chlorine) is 35.5 g/mol. Calculate the molar mass of KCl by adding the molar masses of K and Cl together:
Molar mass of KCl = 39.1 g/mol + 35.5 g/mol = 74.6 g/mol
Next, convert the mass of KCl (55.8 grams) to moles by dividing the mass by the molar mass:
moles of KCl = 55.8 g / 74.6 g/mol = 0.748 moles
Now that you know the number of moles of KCl, you can calculate the volume of the solution using the formula:
volume = moles / molarity
The molarity of the solution is given as 0.225 M, which means there are 0.225 moles of KCl in every liter of the solution. Rearrange the formula to solve for volume:
volume = moles / molarity = 0.748 moles / 0.225 M = 3.32 liters
Therefore, 55.8 grams of KCl is contained in 3.32 liters of the 0.225 M KCl solution.