i posted this before but no one answered. please help me:

A net force of 1.6×10−15 N acts on an electron over a displacement of 5.0 cm, in the same direction as the net force. (a) What is the change in kinetic energy of the electron? (b) If the electron was initially at rest, what is the speed of the electron? An electron has a mass of 9.1×10−31 kg.

part a should be in joules.
part b should be in meters per second.

To find the change in kinetic energy of the electron in Part (a), we can use the work-energy theorem, which states that the work done by the net force on an object is equal to the change in its kinetic energy. The formula for work is given by:

Work = Force × Displacement × cos(θ),

where Force is the net force acting on the electron, Displacement is the distance it moves, and θ is the angle between the force and displacement vectors. In this case, since the force and displacement are in the same direction, the angle θ is 0, and cos(0) = 1.

Therefore, the work done on the electron is:

Work = (1.6×10^(-15) N) × (5.0 cm) × (1).

To convert the displacement to meters, we need to divide by 100:

Work = (1.6×10^(-15) N) × (0.05 m)

Now, let's calculate the work:

Work = 8.0 × 10^(-17) J.

Since the change in kinetic energy is equal to the work done, the change in kinetic energy is also 8.0 × 10^(-17) J.

For Part (b), if the electron was initially at rest, its initial kinetic energy is 0 J. The final kinetic energy is found using the equation:

Kinetic Energy = (1/2) × mass × velocity^2,

where mass is the mass of the electron and velocity is the speed we are trying to find.

Since the change in kinetic energy is given by the work done in Part (a) and is equal to (1/2) × mass × velocity^2, we can set up the equation:

(1/2) × (9.1×10^(-31) kg) × velocity^2 = 8.0 × 10^(-17) J.

Simplifying the equation, we get:

velocity^2 = (8.0 × 10^(-17) J) × (2) / (9.1×10^(-31) kg).

Now, we can solve for the velocity:

velocity^2 = 1.758 × 10^14 (m/s)^2.

Taking the square root of both sides, we find:

velocity ≈ 1.326 × 10^7 m/s.

Therefore, the speed of the electron is approximately 1.326 × 10^7 m/s.

the answer to A is 8X10^/17. You get this by using the work formula, which is the same as change in KE. I don't know how to get B