Water flows over a section of Niagara Falls at a rate of 1.43 × 10^6 kg/s and falls 62.5 m. The acceleration of gravity is 9.8 m/s^2.
How much power is generated by the falling water? Answer in units of MW.
P = 1.43*10^6kg/s * 9.8N/kg * 62.5m =876*10^6W. = 876MW.
To calculate the power generated by the falling water, we need to use the formula:
Power = (mass flow rate) x (acceleration due to gravity) x (height)
Given:
Mass flow rate = 1.43 x 10^6 kg/s
Acceleration due to gravity = 9.8 m/s^2
Height = 62.5 m
Substitute the given values into the formula:
Power = (1.43 x 10^6 kg/s) x (9.8 m/s^2) x (62.5 m)
Solve the equation:
Power = 8530500 kW
Since the question asks for the answer in megawatts (MW), we can divide the value by 1000:
Power = 8530.5 MW
Therefore, the power generated by the falling water is 8530.5 MW.