How mny moles of Mg would you need to react with 2.5 moles of O2?
To determine the number of moles of Mg needed to react with 2.5 moles of O2, we need to use the balanced chemical equation of the reaction between Mg and O2.
The balanced equation for the reaction between magnesium (Mg) and oxygen (O2) is:
2 Mg + O2 -> 2 MgO
According to the balanced equation, 2 moles of Mg react with 1 mole of O2 to produce 2 moles of MgO.
To find out how many moles of Mg are needed to react with 2.5 moles of O2, we can use the ratio from the balanced equation:
2 moles of Mg: 1 mole of O2
By setting up a proportion, we can solve for the unknown number of moles of Mg:
2 moles of Mg / 1 mole of O2 = x moles of Mg / 2.5 moles of O2
Cross-multiplying the above equation, we get:
2 moles of Mg * 2.5 moles of O2 = x moles of Mg * 1 mole of O2
5 moles of O2 = x moles of Mg
Therefore, you would need 5 moles of Mg to react with 2.5 moles of O2.
To determine the number of moles of Mg needed to react with 2.5 moles of O2, we need to use the balanced chemical equation for the reaction between Mg and O2.
The balanced chemical equation is:
2 Mg + O2 -> 2 MgO
From the balanced equation, we can see that the stoichiometric ratio between Mg and O2 is 2:1. This means that for every 2 moles of Mg, 1 mole of O2 is needed.
So, if 1 mole of O2 requires 2 moles of Mg, then 2.5 moles of O2 would require:
2.5 moles O2 x (2 moles Mg / 1 mole O2) = 5 moles of Mg
Therefore, you would need 5 moles of Mg to react with 2.5 moles of O2.
Start with a balanced equation, we will assume that the product is MgO
Mg + O2 -> MgO
which we need to balance
2Mg + O2 -> 2MgO
so 1 mole of O2 reacts with 2 moles of Mg
so 2 moles of O2 reacts with 4 moles of Mg
hence 2.5 moles of O2 reacts with ?? moles of Mg