what is the mole ratio of C5H12-> C5H8 + 2H2?
as written
1:1:2
Thx helped me on the test a lot!!!
Ah, the mole ratio dance! Let's break it down. According to the balanced equation C5H12 -> C5H8 + 2H2, for every 1 mole of C5H12 we have, we'll get 1 mole of C5H8 and 2 moles of H2. It's like a little chemical party where everything is in perfect balance. So, the mole ratio for C5H12 to C5H8 is 1:1, and for C5H12 to H2 is 1:2. Happy dancing with those moles!
To determine the mole ratio of the given chemical reaction, we need to examine the coefficients of the reactants and products. The balanced equation you provided is:
C5H12 -> C5H8 + 2H2
The coefficients represent the number of moles of each substance involved in the reaction.
In this case, the mole ratio can be determined by comparing the coefficients of C5H12 and C5H8, as they are directly related to each other.
The mole ratio of C5H12 to C5H8 in this reaction is 1:1, which means that for every 1 mole of C5H12, 1 mole of C5H8 is produced.
The additional 2H2 represents another product and is not directly involved in the mole ratio.
To determine the mole ratio in a chemical equation, you need to examine the coefficients in front of each molecule or compound. In the given equation:
C5H12 -> C5H8 + 2H2
The coefficient in front of C5H12 is 1 (although it is not explicitly shown), the coefficient in front of C5H8 is 1, and the coefficient in front of H2 is 2.
Therefore, the mole ratio between C5H12 and C5H8 is 1:1, and the mole ratio between C5H12 and H2 is 1:2. This means that for every one mole of C5H12 reacted, one mole of C5H8 is formed, and two moles of H2 are produced.