physics

Determine the resulting temperature when 150g of ice at 0°C is mixed with 300g of water at 50°C

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  1. Heat gained by ice (including after melting) = Heat lost by original liquid water.

    Solve for final temperature, T

    150(80 + T) = 300(50 - T)
    12,000 + 150 T = 15,000 -300 T
    450 T = 3000
    T = 6.7 C

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  2. thanks :)

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  3. 6.7

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  4. GUINEA

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  5. Can you please secribe the value 80+T is what and from where it come

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  6. From Where Do We Have 80+T

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  7. Where do you get 80-T from?

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  8. (150g)(80cal/g°c)= -(300g)(cal/g°c)(T-50°c)

    1200cal= -300cal T + 15000 cal
    300cal T = 15000 - 12000

    300cal T= 3000cal
    T=3000cal/300cal °c

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  9. Where Did You Get 80 + T ?

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  10. latent energy - needed to melt ice, is equivalent to raising the temperature of water by 80°C.
    While melting, 150g of ice will therefore lower the temperature of twice as much by half as much, or 40°C
    The question is therefore equivalent to mixing 150g of water at 0°C with 300g of water at 10°C.
    6,7°C

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