Determine the resulting temperature when 150g of ice at 0°C is mixed with 300g of water at 50°C
Heat gained by ice (including after melting) = Heat lost by original liquid water.
Solve for final temperature, T
150(80 + T) = 300(50 - T)
12,000 + 150 T = 15,000 -300 T
450 T = 3000
T = 6.7 C
Can you please secribe the value 80+T is what and from where it come
From Where Do We Have 80+T
Where do you get 80-T from?
GUINEA
latent energy - needed to melt ice, is equivalent to raising the temperature of water by 80°C.
While melting, 150g of ice will therefore lower the temperature of twice as much by half as much, or 40°C
The question is therefore equivalent to mixing 150g of water at 0°C with 300g of water at 10°C.
6,7°C