The area of largest isosceles triangle that can be drawn with one vertex at the origin and with others on a line parallel to and above the x-axis and on the curve y=27-x^2 is....

A) 108
B) 27
C) 12 root 3
D) 54
E) 24 root 3

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  1. D) 54

    One vertex is x,y and the other is -x,y
    y= 27 - x^2

    A= 1/2 BxH

    B = x - -x = 2x
    H = 27 - x^2

    A = 1/2 * 2x * (27 - x^2)
    Take the derivative, find when the derivative is = 0 then plug that back in to get dimensions and solve for area.

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