What is the concentration of nitrate ions in a solution that contains M aluminum nitrate?

sorry .900 M

Al(NO3)3 contains 3 NO3^- ions per 1 molecule of Al(NO3)3; therefore, a solution 0.900 M in Al(NO3)3 must be 3*0.900M in NO3^-

To determine the concentration of nitrate ions in a solution of aluminum nitrate, we need to know the molarity of the aluminum nitrate solution (M).

Aluminum nitrate (Al(NO3)3) dissociates in water to form one aluminum ion (Al3+) and three nitrate ions (NO3-).

Since the formula unit of aluminum nitrate contains one aluminum ion and three nitrate ions, the molar ratio of nitrate ions to aluminum nitrate is 3:1.

Therefore, the concentration of nitrate ions (NO3-) in a solution that contains M aluminum nitrate would be 3 times the molarity of aluminum nitrate.

Concentration of nitrate ions = 3 * M

To determine the concentration of nitrate ions in a solution of aluminum nitrate, we will need to know the molarity (M) of the aluminum nitrate solution. Molarity is a measure of the number of moles of a solute (in this case, aluminum nitrate) dissolved in one liter of solvent (usually water).

Once we know the molarity of aluminum nitrate, we can use the chemical formula of aluminum nitrate, Al(NO3)3, to determine the concentration of nitrate ions. In one molecule of aluminum nitrate, there are three nitrate ions (NO3-).

To calculate the concentration of nitrate ions in the solution, we can use the following formula:

Concentration of nitrate ions (in M) = Molarity of aluminum nitrate (in M) x 3

For example, if the molarity of the aluminum nitrate solution is 0.5 M, then the concentration of nitrate ions would be:

Concentration of nitrate ions = 0.5 M x 3 = 1.5 M

Therefore, the concentration of nitrate ions in the solution that contains 0.5 M aluminum nitrate would be 1.5 M.