Please help me understand!..If you have 100.0mL of a 30.0% aqueous solution of ethanol, what volume of water is in the solution?
Is that 30.0% v/v or some other unit?
If v/v, that means 30.0 mL ethanol in enough water to make 100 mL solution. How much water is that? I don't know since the volume of ethanol and the volume of H2O are not additive. (Meaning that 50 mL ethanol and 50 mL water equals approximately 95 mL total volume).
70 ml of water
30 mL ethanol + 70 mL H2O does not equal 100 mL solution. It will be close but it will be less than 100 mL.
To determine the volume of water in the solution, we need to find out how much of the 100.0mL is occupied by ethanol.
The given information states that the solution is a 30.0% aqueous solution of ethanol. This means that 30.0% of the solution is ethanol, and the remaining percentage must be water.
To find the volume of ethanol in the solution, we can use the formula:
Volume of ethanol = Percentage of ethanol × Total volume
From the given information, we know that the percentage of ethanol is 30.0%, and the total volume is 100.0mL.
So, Volume of ethanol = 30.0% × 100.0mL = 30.0mL
To find the volume of water, we can subtract the volume of ethanol from the total volume:
Volume of water = Total volume - Volume of ethanol = 100.0mL - 30.0mL = 70.0mL
Therefore, there is 70.0mL of water in the solution.