Math/Algebra

y^2-4y-12=0

Please help. :)

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  1. The simplest solution is by factorization:
    y^2-4y-12=0
    (y 2)(y 6)=0
    Since 2*6=12, 6-2=4
    are what you are looking for.
    Now we need to figure out the signs:
    -12 means that exactly one of the constants (2 or 6) carry a negative sign.
    If we give assign 2 and -6, we get 2-6=-4, which is what we want, so:
    (y+2)(y-6)=0
    Can you do take it from here?

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  2. In google type:
    "quadratic equation online"

    When you see list of results click on:

    webgraphingcom/quadraticequation_quadraticformula.jsp

    In rectacangle type: y^2-4y-12=0

    and click option solve it

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